构造List

=List.Select(List.TransformMany({1..4},(i)=>{1..4},(x,y)=>{x..y}),each List.Sum(_)>0)

这个简洁，方法比较好

练手一下：

1. let
   
2. 
     myfun = (a,lst)=> List.Transform(
   
3. 
     {0..(List.Count(lst)-List.PositionOf(lst,a)-1)},each
   
4. 
     List.Range(lst,List.PositionOf(lst,a),(_+1))),
   
5. 
     Source = List.Combine(List.Combine(List.Transform({1..4},each myfun(_,{1..4}))))
   
6. 
   in
   
7. 
     Source
   
8. 
   

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谢谢，辛苦了

(PQ)M Code参考解法

1. let
   
2. 
   SrcList= {2,3.3,1.5,6},
   
3. 
   LoopFunc =(pos as number) => List.Generate(()=>[l={SrcList{pos}},i=1],each [i]<=List.Count(SrcList)-pos,each [l=List.Range(SrcList,pos,[i]+1),i=[i]+1],each [l]),
   
4. 
   Result = List.Combine(List.Transform(List.Positions(SrcList),LoopFunc))
   
5. 
   in
   
6. 
   Result

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我是个凑数的。。。

1v1飘过

支持你哈...................................

努力学习中

一直在看

一直在看